Input Pins – Low Impedance

I have a programme running correctly but the input pins seem to be of low impedance, rather than the high impedance expected.
Each input current is about 4 mA. The chip is a Pic 16F84 with port A not used and pulled low thru 10 K resistors. Input and output is on port B. Input pins are pulled high with 10K. Under test on the bench a power supply is used to connect to the pin and simulate high and low inputs, and the 4 mA is then measured. However, when used in the application, the signal is from a data acquisition system which can only supply 2.5 mA max.
I am not able to understand why, from the code attached, a pin seems to work correctly as an input but is not of high-impedance.
Any help would be much appreciated.
Regards,
GraemeJ.

Code:

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‘pump driver.
‘Pic 16F84
DEFINE OSC 4
‘----------[constants and variables]------------
pump        VAR    PORTB.0        ‘switch pump on/off
info        VAR    PORTB.1        ‘data being collected
nsamp        VAR    PORTB.2        ‘new sample required
autotrig    VAR    PORTB.3        ‘trigger autosampler
relay        VAR    PORTB.5        ‘pump relay
sampler    VAR    PORTB.6                ‘goto autosampler position
led        VAR    PORTB.7        ‘switch on led

‘----------[initialisation]------------------------
PORTB    = %00000000            ‘all variable values = 0
Pause 10
TRISB        = %11110000        ‘B.0 B.3 inputs, rest outputs.
Pause 10
‘----------[Main]--------------------------------
begin :        if pump = 0 then pumpoff    ‘hold pump off   
        High    relay            ‘else switch it on
        Pause 5
datasw :    if info  = 0 then sampsw    ‘if no data flash led
        High    led            ‘else keep led on
        Pause 5
        Goto begin
Sampsw :    if nsamp = 0 then ledoff    ‘flash led
        Pause 800
        High led
        Pause 800
        Low led
        Pause 5
        Goto begin
Pumpoff :    Low relay            ‘keep pump off
        Pause 5
        Goto datasw
Ledoff :    Low led
        Pause 5
        Goto begin
End

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Hi,
Any chance the powersupply voltage used to simulate the inputs are higher than Vdd of the chip? That might (depending on how much higher it is) forward bias the clamping diode on the input, increasing the current going into the pin.

/Henrik.

Code:

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TRISB                = %11110000                        ‘B.0 – B.3 inputs, rest outputs.

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Your TrisB setting is wrong. To have B0 - B3 as inputs then the TrisB should be the other way around

TrisB = %00001111

Cheers

Al.

Quote:

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Originally Posted by aratti

Code:

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TRISB        = %11110000            ‘B.0 – B.3 inputs, rest outputs.

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Your TrisB setting is wrong. To have B0 - B3 as inputs then the TrisB should be the other way around

TrisB = %00001111

Cheers

Al.

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Al nailed it, the way "I" keep those straight is 0 looks like the letter O for output
and 1 looks like the uppercase letter I for Input, works for me anyway.

Thanks everyone. I feel very foolish. My only excuse is that its quite a while since I have been near a uP.
GraemeJ.

NEVER feel foolish about asking a question, for every poster who has the guts to ask there are many who do not and have the same question, so on their behalf, thanks for asking!