Making Array of two ports

Hi all PBP Artists!
i'm trying to create an array of two ports -porta and portc (16f630)

Output VAR bit[9]

SYMBOL Output[0] = PORTA.0
SYMBOL Output[1] = PORTA.1
SYMBOL Output[2] = PORTA.2
SYMBOL Output[3] = PORTA.3
SYMBOL Output[4] = PORTA.4
SYMBOL Output[5] = PORTC.0
SYMBOL Output[6] = PORTC.1
SYMBOL Output[7] = PORTC.2
SYMBOL Output[8] = PORTC.3
SYMBOL Output[9] = PORTC.4

for x = o to 9
Output[x] = 1
next x

it doesn't work! where is my mistake?

May be help on the thread " Word arrays and EEPROM"

Alain

3 things:

1. your Array size must be 10 instead of 9
2. for to next loop=o or loop=0 ?
3. you didn't set your TRIS register. TRISC=0 : TRISA=0

BUT i don't know if you can address i/o in array... :(

Hi John,

There's no way to do that with standard PBP commands. Normal PBP arrays must be completely contiguous. However, we can create a new command with a little assembly language.

This isn't exactly what you were looking for, but it does accomplish the exact same thing.

Put this code near the top of your program.

Code:

---

'------[ PortOut macro ]----------------
Temp_idx    VAR  byte
Temp_State  VAR  BIT

ASM
PortOut  macro idx, state
    MOVE?BB idx, _Temp_idx
    MOVE?CT state, _Temp_State
EndASM
    if Temp_idx < 5 then
        PORTA.0[Temp_idx] = Temp_State
    else
        Temp_idx = Temp_idx - 5
        PORTC.0[Temp_idx] = Temp_State
    endif
@  endm
'---------------------------------------

---

Then you can simply do this...

Code:

---

for x = 0 to 9
@  PortOut  _X, 1 
next x

---

With this code, the state("1" in this case) must be a constant. I did it that way just to be consistant with your request.

If you wanted to use a variable instead, simply change this line in the PortOut routine...

MOVE?CT state, _Temp_State

-- changed to --

MOVE?TT state, _Temp_State

HTH,
   Darrel