I need to send a 5 us pulse to a pin. I'm using a 16F88 at 8 MHz and need to keep processing overhead down.
Which is faster, using PULSOUT or this:
PIN=1
PAUSEUS 5
PIN=0
I have to do this at different (and varying) times on 5 different pins.
Russ
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I need to send a 5 us pulse to a pin. I'm using a 16F88 at 8 MHz and need to keep processing overhead down.
Which is faster, using PULSOUT or this:
PIN=1
PAUSEUS 5
PIN=0
I have to do this at different (and varying) times on 5 different pins.
Russ
At 8mHz, the minimum PAUSEUS is 12uS (14-bit cores).
Minimum PULSOUT is 5uS.
Apples and Oranges (no tomatoes) :)
Although, here's an ASM delay routine that can do down to 1uS at 8mHz.
http://www.picbasic.co.uk/forum/show...8&postcount=22
Then just ...It only works with constants though, no variables. :(Code:PIN=1
@ DelayUS 5
PIN=0
hth,
Here's a simple macro I use for short delays.
It provides delays from a single instruction cycle up to 256. For a 5uS delay at 8MHz justCode:asm
DelayCycles macro ncy ; ncy can be from 1 up to 256
local n
n set (ncy) ; assign ncy value to label n
while n > 2 ; inserts goto $+1 while n > 2
goto $+1 ; burn 2 cycles
n set n - 2 ; n = n - 2
endw
; handle left-overs
while n > 0 ; 1 nop for odd numbers
nop ; burn 1 cycle
n set n - 1 ; n = n - 1
endw
endm
endasm
Main:
HIGH 0
@ DelayCycles 1 ; adds 1 nop
LOW 0
@ DelayCycles 5 ; adds 2 x goto $+1 and 1 x nop
GOTO Main
use @ DelayCycles 10
Hello
Here a simple way to do a fast pulse out delay. At 8mhz setting portb =1 takes 2 cycles or 1us.
Portb.1 =1
Portb.1 =1
Portb.1 =1
Portb.1 =1
Portb.1 =1
Portb.1 =0
Regards
Oh, <i>DUH!</i> I <u>did</u> know about that minimum; I can't believe I forgot it!Quote:
Originally Posted by Darrel Taylor
Interestingly, if you give PAUSEUS anything less than 12 (at 8 MHz), it defaults to 12. I verified this on the scope.
Also from looking at the scope: Using PULSOUT takes longer despite allowing the shorter pulse length.
Mark, thanks for the idea. Ideally, I'd like to have a 3 us, so I'll play with your suggestion and see how it looks.
While Mark's way is functional, I prefer other methods to avoid thinking the repetitive PortB.1=1 isn't a typo or accidental copy/paste.
There are two more ways to do it. Using NOP's makes it very clear that it is a delay.
PortB.1=1
asm
NOP
NOP
NOP 'repeat as necessary
endasm
PortB.1 = 0
However, using GOTO's executes in the same amount of time, but uses half the program space. You have to be cautious of pages, though. The best way is with the basic goto command, but then you might get excess overhead with page checking.
Portb.1 = 1
goto skip1 'kills a minimum of 2 cycles
skip1:
goto skip2
skip2:
portb.1=0
Russ,
Using the same idea you can control all you pins at same time. Its not pretty or clever, but it works
PortB = %00000001 ;pin 0 high 3us
PortB = %00000001
PortB = %00000001
PortB = %00000010 ;pin 0 low, pin 1 high 3us
PortB = %00000010
PortB = %00000010
PortB = %00000100 ;pin 1 low, pin 2 high 3us
PortB = %00000100
PortB = %00000100
PortB = %00000000 ;all pins off
Loop etc
Tenaja is your name Don L?
Repetitive port settings on 16F (and lower) devices must also take into account the read/modify/write timing. If you place two consecutive settings in a program, you could end up with a random output setting because of the r/m/w delays.Quote:
Originally Posted by mark_s
No.Quote:
Tenaja is your name Don L?
Don L. lives in Arizona, and sells stuff on ebay :)Quote:
Originally Posted by mark_s
Edit: Oh and he will autograph his books too . . .
My mistake he goes by "tinaja" not Tenaja. Don Lancaster was a big influence for me in the late 70's and early 80's.