Reducing PIC current to as low as possible...

Reduce current consumption:
Hello, I am trying to reduce the current consumption of my PIR transmitter program. I see 700uA on my digital multimeter while the PIC is sleep. Yes, this current is only for the PIC and no external circuitry included.
I would like to ask if someone can suggest any changes to the code so the current can be reduced to as much as possible. Many Thanks

Code:

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DEFINE NO_CLRWDT

'// For PIC12F635
         
@ __CONFIG _INTRC_OSC_NOCLKOUT & _WDT_OFF & _PWRTE_ON & _MCLRE_OFF & _CP_ON & _BOD_OFF & _CPD_ON & _IESO_OFF & _FCMEN_ON & _WUREN_OFF

  TRISIO = %1111110
  OPTION_REG = 128
  GPIO.0 = 0
transmit:
‘PIC does its job here
goto rest

rest:
        while GPIO.0=1
        goto encode
        WEND
        IOCA.0 = 1        ' int on change enabled for GPIO.0
    INTCON = %00001000
    @ SLEEP
    INTCON.0 = 0      ' clear wake up on change int flag

prepare:
‘PIC does its job here
goto transmit
return

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Anyone out there?

I would make sure the unused input pins are tied high or low.

Running it on 2V would reduce the current.
Also, lower osc speed would reduce the current, too.

Check the datasheet for low power features.

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Quote:

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Originally Posted by sayzer

Also, lower osc speed would reduce the current, too.

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Can this be a good & reliable option:

Code:

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        OSCCON=48 ' reducing Osc speed before going to sleep
        PAUSE 1
    INTCON = %00001000 ' global ints disabled, int on change enabled
    @ SLEEP            ' put PIC to sleep
        OSCCON=96 ' back to normal speed

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Not much help there since the oscillator is disabled during sleep...;o)

I'd like to see your schematic to understand where you might be losing current. The PIC cannot consume so much in sleep mode.