decrypted data

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- 11th February 2009, 13:57
RAYMON

decrypted data

Je cherche a decrypted data and apparently no one understands the method of encryption.
I think what is encrypted but I can not find how, and you
how you have done to conceal or render unreadable data in a small eeprom?

http://www.asmfr.com/forum/sujet-ASM...E_1267692.aspx

To clear the text:
1212131323323434 = 45454556567878989890
VUQR5O UKEL7Y N7MF69 OANL17 NNMOIK RFJMW8 4PUO2V EXAXGE RNNNL2 ZQLIXZ
NKXZLI XJMZZJ JKFNIZ DHT5DR H0FLRD ZPH4DZ VR3XDT JDXVPL DJJDHP LDLJDX
VRFQTH 6BZTNB HTDVJB VVBBVZ LNVPDL V2XBTX HZT4XB TNDR2F BTJDRF JJZXPX
X29JJX Z23XJZ T83QRJ ZZVJFD VTFFH
- 11th February 2009, 14:13
Acetronics2

Hi, "KAD" ou whatever your pseudo ...

No use to SPAM every PIC Forum on the NET ...

add to that asm

( which Pics used ??? ... I'd really like to know )

Code:

00405853 . 50 PUSH EAX 00405854 . 52 PUSH EDX 00405855 . 8BD1 MOV EDX,ECX 00405857 . E8 ABFFFFFF CALL VIEW1.00405807 0040585C . 5A POP EDX 0040585D . 58 POP EAX

is not exactly the main language here ...

Encore un génie qui restera méconnu ...

Alain
- 12th February 2009, 11:15
RAYMON

cryptage

Hi

This is a pic 16F876, the party is on the site is the program reception
as hyperterminal.

Esque table that will use the program to encrypt or decrypt is
used to rebuild his method?

It decryption routine that I can not locate, because the encryption is done
in an electronic circuit that sends data to your PC.

Maybe xor encryption or modifications ascii characters to scramble
the text?

a good knowledge of ASM and can surely find the solution and decrypt
it easily, it's hard for beginners.

I hope to find help on this forum

merci
A+
- 12th February 2009, 13:56
Jumper

What are you looking for?

Are you looking for:

A: A way to encrypt and decrypt your own data using PBP. If this is what you are looking for there are several ways to do it. TEA, XTEA and so on.. or a more simple XOR encryption

B: Get help to decrypt information from a different source than your own?

??
- 13th February 2009, 11:05
RAYMON

eeprom

Hello

I think it's complicated, but you must know.
And you how you could have done to protect data of a eeprom 24lc512
Or perhaps the program that sends false with true and blurs the text.
thank you for your help
- 14th February 2009, 10:28
RAYMON

1 Attachment(s)

Decrypte

helo

Apparently in order to decode it must test all the values from 0 to 255 and
My case I'm only 10 digits? 0 to 9. As is always numeric characters
over a length of 40 characters, there will be several repetitions of figure?

If coding for each digit is a different value to not be able to compare
compared to its own value and its relative position in the text encrypt
so it will not have duplicates so it must be visible in the text by encrypting
report its presence (1 time only) or all the characters this one
both in the text after eliminating pressent characters several times, remains in the form code.

adqtuy / egil / pjkn / obfxzh
(1 time) / (2 times) / (3 times) / (4 5 8 9 times)

(A d t q u y) once in the text

9 9 9 9 8 8 8 8 7777 6666 = 5555 4444 3333 2222 1111
adqtuy - - - - - - - - - - -----------------------------------

Example: 1234567890123456 = 78900987654321987654
or 1111111111111111 = 11111111111111111111
or 1111777511456421 = 66880044411009922336

and the first digit has a different value of the second and so on. .... So the first 1 will be A, B will be 1 second and so on, more characters to scramble.

So with 10 digits and can not exceed 255 reduces its encryption.

Converted to decimal 0 = 48 and 30 in Hexa
255: 30 = 9 MAX 255: 48 MAX = 6

9 converted to decimal = 57 and 39 in Hexa
255: 39 = 7 MAX 255: 57 = 65 MAXI

So the division, subtraction, multiplication will not be used and still adding
that may serve, by inference we can easily find its encryption method.

Permuting rest but will have identical characters and easily detectable.
or the formula in exel and must be tested from 0 to 255.

EXEL SOUX = ((0 * C86/256)-T (0 * C86/256)) * 256

EXEL SOUX = ((255 * C86/256)-ENT (255 * C86/256)) * 256

Which are coded and which are repeated, have tested the formula in exel there are chances of
Find a match and that number is found the rest will be easy.

I clear the text and I encrypt the text, and my friend only encryption key but
do not know the plaintext

Its key it can decrypt and discover the plaintext, I guess it is not
also complicated, because the figures have the same value once encrypt

Example: A value will b 5, an R-value will be 0 ... etc ...

So they will not take the value of another figure, and will not be repeated
in the encrypt text, it will always be one (b for 5) and no other (b)?
significantly reduced its combinations.

On the forums:

Simply because this key will affect the interference characters by their ASCII value.

ASCII codes represent the letters A to Z (eg "A" is 65, "B" is 66, ...) and all the figures and the other symbols on your keyboard.

But the problem is that ASCII values range from 0 to 255.

The most important part of encryption is the way to blur the text.
ASCII does not constitute an encoding of secret is to encrypt the ASCII code
Encryption using the following:
C note on the encryption feature which, at any integer n in [0, 255] combines the remainder of the division by 256 of 7n. Let C (n) the rest. We use the formula "= MOD (7 * n, 256).