10Bit ADCIN into 8-Bit WORD?

Clarify for me, please: I use: "DEFINE ADC_BITS 10" to indicate I'm going to read an analogue value with 10 bits, then later use "ADCIN 2, J_MidPnt", when the value is put into a variable "J_MidPnt" which had been declared a VAR of type WORD. I thought WORDs were 8-bits... What happens to the other two bits? I'm a confused NewBe (Obviously) Thanks!!!!

How about if a BYTE is 8 bits and a WORD is 16 bits. Would that make things easier? Now you are so lucky because a WORD is actually 16 bits :) and you are now less confused.

Immediate accurate information. You gotta love it. Thanks!

Just make sure you use the LOW 10 bits of the Word variable, or you will get really funny results. There is a function in the PIC that makes the ADC result left or right justified but maybe you have found this already?