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precision
- 8th April 2007, 04:23
My variable is

B0 var byte
B1 var byte
B2 var byte
C0 var byte

B0 = 1
B1 = 2
B2 = 3



I want C0 = 123
( C0 = B0 B1 B2 )


-------------------

C0 = B0 DIG 1
C0 = B1 DIG 2
C0 = B1 DIG 3

Not working ????

in pbp manual, 4.17.7 , example is to Extraction, not combine.

.

Jerson
- 8th April 2007, 05:27
B0 = 1
B1 = 2
B2 = 3



I want C0 = 123
( C0 = B0 B1 B2 )



Try this

C0 = (B0*100)+(B1*10)+B2

or you can do it like this
C0 = B0*10
C0 = (C0+B1)*10
C0 = (C0+B2)

Happy Easter
Jerson

paul borgmeier
- 8th April 2007, 05:29
'putting it together
B0=1
B1=2
B2=3
C0=B0*100+B1*10+B2 ' C0=123

taking it apart
C0 = 456
B0=CO DIG 0 ' B0 = 6
B1=C0 DIG 1 ' B1 = 5
B2=C0 Dig 2 ' B2 = 4

precision
- 8th April 2007, 09:53
Thanks Jerson
Thanks paul borgmeier

its working.

Thanks