View Full Version : How long does a Bourns/74HC14 debounce filter take
Demon
- 23rd August 2024, 22:14
From my observations, it takes 93usec for a signal to travel through a Bourns debounce filter and a 74HC14 Schmitt Trigger.
9735
(my eyes just gloss over when I try to figure this out from a datasheet :D )
richard
- 24th August 2024, 02:39
tor = RC [rc time constant]
falling tor = 10k*0.1uF = 1mS
smit trigger will definitely be triggered @ tor*2 = 2 mS
rising tor = 20k*0.1uF = 2mS
smit trigger will definitely be triggered @ tor*2 = 4 mS
9736
Demon
- 24th August 2024, 03:59
I'm using 10K - 0.01uF, exactly like here:
9737
Along with Toshiba's TC74HC14AP Schmitt trigger (I'm guessing I'm supposed to look at propagation delay ? ):
https://mm.digikey.com/Volume0/opasdata/d220001/medias/docus/1134/TC74HC14.pdf
My math uses fuzzy logic at the best of times. :D
richard
- 24th August 2024, 05:45
I'm guessing I'm supposed to look at propagation delay ?\
propagation delay has virtually zero impact on the debounce time
tor = RC [rc time constant] is the most significant factor by 3 orders of magnitude
falling tor = 10k*0.01uF = 100uS
propagation delay 0.021 uS
debounce time is the time taken for the st input voltage to fall from vcc to the
Negative threshold voltage for the SCHMITT trigger ie 2*tor
rising tor = 20k*0.01uF = 200uS
debounce time is the time taken for the st input voltage to rise from ground to the Positive threshold voltage for the SCHMITT trigger ie 2*tor
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