Pic Basic help

[Klaus]

OK, this is probably really simple but I can't seem to make it work. I'm using a IF THEN statement like this: IF (variable) = (a number) THEN (Label)
Label: some code
END IF
When I try to compile, the error message I get is END IF without a matching IF---THEN
Basically, what I am trying to do is jump out of a loop to "Label" if the variable is a specific number.
Reading the PICBASIC compiler manual, I can't see what I'm doing wrong. Thanks for any help.
Klaus

[mister_e]

Start:        
        IF MyVar=9 THEN
            LCDOUT $FE,1,"How's Santa today?"
            ELSE
                GOSUB PassGoAndClaim200Bucks
            ENDIF
        
        IF MyVar=8 THEN
            PAUSE 500
            LCDOUT $FE,1,"Doh!"
            STOP
            ENDIF            
            
        IF MyVar=7 THEN WhoLetTheDogsOut
      
        GOTO Start
        '
        '
        '
PassGoAndClaim200Bucks:
        '
        '   Plah Plah Plah
        '
        RETURN 
        '
        '
        '
WhoLetTheDogsOut:        
        '
        '   Woo... Woo... Woo
        '
        GOTO Start

Make sure you didn't forgot a ENDIF somewhere in your code while editing it... yeah it happen

[HenrikOlsson]

Hi Klaus,
When you have a one-line IF statement you don't use EndIf. So simply:

If A = B Then myLabel

should do it.

/Henrik.

[Klaus]

Thanks very much. Leaving out the ENDIF worked.