Multiplexer address control..

[retepsnikrep]

I have a HTC4067 16x1 multiplexer, it's controlled by four lines S0, S1, S2, S3
I have these all connected to Port B pins 4,5,6,7 respectively on my pic. This could be reversed to 7,6,5,4 if that helps.
I'm after ideas on how to step through the input options 0-15 as per the truth table below as efficiently as possible.

i.e. select input 0, then 1, then 2 etc etc in sequence..

Increment a byte from 0 to 15 and mask off the 4 high bits?

Ideally I don't want to effect the output/status etc on the PortB 0,1,2,3 during this operation..

[pedja089]

If you are using PIC 18F, then use simplest solution is
LATB.4=Control.0
LATB.5=Control.1
LATB.6=Control.2
LATB.7=Control.3

EDIT:
For PIC16

PortBCopy var byte

PortBCopy = PORTB
PortBCopy .4=Control.0
PortBCopy .5=Control.1
PortBCopy .6=Control.2
PortBCopy .7=Control.3
PORTB=PortBCopy

[retepsnikrep]

Yes thanks, but how to step through the options in the most efficient way without disturbing ports B0-3

[pedja089]

for control = 0 to 15
LATB.4=Control.0
LATB.5=Control.1
LATB.6=Control.2
LATB.7=Control.3
next control

[Art]

It would be quicker if you used the port bits 0-3 instead, so you could just increment the port b value.
The quickest way also depends where the enable bit is connected.

[Dave]

Pedja089, In your suggested code you are treating "Control" as an array. If it is not then you are just resetting the LATx bits 16 times.