BCD to 7-segment issues


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  1. #1
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    Default BCD to 7-segment issues

    I am driving a 7-segment display with an HC4511 BCD to 7-segment decoder.

    The input of the 4511 is connected to PORTB 0-3.

    I have a byte value that contains the number I want to display.

    Would something like this work?

    Code:
    portB.0 = MyByte.Bit0
    portB.1 = MyByte.Bit1
    PortB.2 = MyByte.Bit2
    PortB.3 = MyByte.Bit3
    In other words, would the lower 4 bits of PORTB follow what my byte is doing? When I update my byte, would PORTB then change to reflect the new value? Or am I on the wrong track here?

    If I am on the wrong track, how do I make the lower 4 bits of PORTB mirror the lower 4 bits of my byte, without affecting the upper 4 bits of PORTB? The upper 4 are being used for other things.

    Thanks,

    Andy

  2. #2
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    Default

    Code:
    PORTB = (PORTB & $F0) | (MyByte & $0F)
    DT

  3. #3
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    Default Re: BCD to 7-segment issues

    Quote Originally Posted by Darrel Taylor View Post
    PORTB = (PORTB & $F0) | (MyByte & $0F)
    Wow! So simple. I played with it on paper and that works great. I did have the idea of an OR in my head, but couldn't figure out how a bit that was set to a '1' could change back to a '0'.

    Actually, now that I think of it, since MyByte is only going to be zero to nine, I think I could get away with this:

    Code:
    PORTB = (PORTB & $F0) | MyByte
    Thanks!
    Last edited by andywpg; - 9th November 2012 at 21:56.

  4. #4
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    Default Re: BCD to 7-segment issues

    It would be great, if someone with better PBP knowledge can explain, what that code actually does (how)

  5. #5
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    Default Re: BCD to 7-segment issues

    Let us suppose bits 5 and 6 of portb are set and 4 is displayed on the 7 seg display and we want to display 5
    portb will be %01100100
    (portb & $F0) will clear the lower 4 bits of portb leaving bits 5 and 6 unchanged.

    01100100 &
    11110000
    ========
    01100000 result A

    (mybyte & $0F) will clear the top 4 bits of mybyte
    11000101 &
    00001111
    ========
    00000101 result B

    we now OR ( | ) result A with result B

    01100000 OR
    00000101
    ========
    01100101

    Bits 5and 6 of portb are unchanged and the lower 4 bits are set to 5
    If mybyte is never going to be greater than 9, (mybyte & $0F) can be replaced by mybyte

    See bitwise operators in the manual

  6. #6
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    Default Re: BCD to 7-segment issues

    Thanks! So it is logical operation with pre-defined masks.

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