Multiple AND's

[tazntex]

This seems to work:

If (a = B) && (a = c) && (a = d) && (a = e) && (a = f) && (a = g) &&(a = g) && (a = i) && (a = j) && (a = k) && (a = l) THEN
m = 1
else
m = 0
endif

But is this the only way to do this?

Thanks

[Melanie]

There are as many ways as you have imagination...

	m=0
	If (a = B) then
		if (a = c) then
			if (a = d) then
				if (a = e) then
					if (a = f) then
						if (a = g) then
							if (a = h) then
								if (a = i) then
									if (a = j) then
										if (a = k) then
											if (a = l) then m=1
											endif
										endif
									endif
								endif
							endif
						endif
					endif
				endif
			endif
		endif

That one kinda looks pretty...

[sayzer]

IF (a*a*a*a*a*a*a*a*a*a*a) =  (a + b+ c +d +e + f +g +h +i +j +k +l) THEN DO

Could this work?


_____________-

[Melanie]

I initially thouhgt doing the addition thing... but it wouldn't work...

(a*11)=(b+c+d+e+f+g+h+i+j+k+l)

looks fine untill you consider the equation would still be true if one of the values was less than a, whilst another of the values was greater than a by the same amount.

[Darrel Taylor]

Another way ...

Idx   VAR BYTE
Vars  VAR BYTE[12]
  a   VAR Vars[0]
  b   VAR Vars[1]
  c   VAR Vars[2]
  d   VAR Vars[3]
  e   VAR Vars[4]
  f   VAR Vars[5]
  g   VAR Vars[6]
  h   VAR Vars[7]
  i   VAR Vars[8]
  j   VAR Vars[9]
  k   VAR Vars[10]
  l   VAR Vars[11]
  m   VAR BYTE
  
For Idx = 1 to 11
    IF a != Vars[Idx] THEN m = 0 : GOTO VarTestDone
NEXT Idx
m = 1
VarTestDone:

[Acetronics2]

Hi,TaznTex

As it looks close to logics ... Could you tell what kind of variables are "a" to "l" ???

Alain