1. Have a 4x1N4004 or 4007 diodes as a rectifier, or even better a bridge rectifier (4 pins) for 500Volts/2-5Amps.
2. On the AC line, fuse and a small resistor for the in-rush currents, say 2-5 ohms.
3. After rectification a capacitor of 220uF/500 Volts.
4. Calculate maximum voltage as 250 Vac x 1,41=353 Volts DC on te capacitor.
5. Calculate the total drop of LEDs say 332.5 Volts. Calculate the number of LEDs 332.5/3,5= 95 LEDs.
6. Calculate the resistor to be in series as (353 - 332.5)/.03 = 680 Ohms
7. Calculate the power of the resistor .03 x .03 x 680= 620mW. I would go x4 to set it at 2,5Watts
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