Inverse of COS

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  1. - 1st June 2005, 12:46 #1
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    Default Inverse of COS

    Can anybody help me find ArcCos?

    Regards,
    uuq
  2. - 1st June 2005, 15:37 #2
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    Dwayne
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    Hello uug1,

    In order to do this, you must use the taylor series..

    Go to the bottom of this link... IT gives a LOT of info.

    http://www.picbasic.co.uk/forum/show...ghlight=Taylor

    Dwayne
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  3. - 1st June 2005, 15:52 #3
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    Alternatively, look at the PROTON+ compiler.

    This does true floating point calculations including trigonometry.
  4. - 3rd June 2005, 10:20 #4
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    Default InvCos

    I tried with Taylor series but no good.
    For angles less than 45 degrees, the code seem to work ok, but for larger angles the deviation is high.

    I have decided to use interpolation with select.

    Appreciate the help I got from this place.
  5. - 3rd June 2005, 20:44 #5
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    languer
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    You may also want to look here:
    http://www.emesys.com/BS2math3.htm
  6. - 6th June 2005, 04:17 #6
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    Thanks languer for the article. I think it will help.
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