ºC -> ºF Conversion

[CocaColaKid]

I've hit a road block in converting temperature from celcius to fahrenheit. I know:

ºF = (ºC*18)/10+32

This works fine for positve temperatures but not for negative. I discovered:

ºF = 32-((-ºC*18/10+32)-32)

This formula works fine until I get to the negative numbers in ºF. In ºC there is a bit set indicating that the number presented is a negative.

Any ideas would be greatly appreciated.

[mister_e]

what is the range of your positive and negative Temperature reading before converting ???

i mean positive : from x to y
negative : from a to b

I don't know what is your hardware setting but you can probably test the borrow bit and do some math with. Maybe the range will tell a better solution in this case.

[CocaColaKid]

I'm using the DS18S20 which is a celcius chip with a range or -50C - 125C.

[Luciano]

Hi!

See page 13 of the PDF.

From the Nuts and Volts magazine:

There’s A New Stamp In Town - Part 1
Column #68, December 2000 by Jon Williams:

PDF file:
http://www.parallax.com/dl/docs/cols...2/col/nv68.pdf

Basic stamp code:
http://www.parallax.com/html_pages/d...wnloads_V2.asp


Best regards,

Luciano


* * *

In general using the calculator:


Convert -15 Celsius to Fahrenheit:

-15 * 9/5 = -135/5 = -27
-27 + 32 = 5 F


Convert -10 Celsius to Fahrenheit:

-10 * 9/5 = -90/5 = -18
-18 + 32 = 14F

Convert -273 Celsius to Fahrenheit:

-273 * 9/5 = -2457/5 = -491.4
-491.4 + 32 = -459.4F

[languer]

The following Maxim appnote shows some c-code to convert from the sign-extended two's complemented value:

temp_msb = get[1]; // Sign byte + lsbit
temp_lsb = get[0]; // Temp data plus lsb
if (temp_msb <= 0x80){temp_lsb = (temp_lsb/2);} // shift to get whole degree
temp_msb = temp_msb & 0x80; // mask all but the sign bit
if (temp_msb >= 0x80) {temp_lsb = (~temp_lsb)+1;} // twos complement
if (temp_msb >= 0x80) {temp_lsb = (temp_lsb/2);}// shift to get whole degree
if (temp_msb >= 0x80) {temp_lsb = ((-1)*temp_lsb);} // add sign bit
temp_c = temp_lsb; // ready for conversion to Fahrenheit
temp_f = (((int)temp_c)* 9)/5 + 32;

You may want to check this as well, http://www.rentron.com/PicBasic/one-wire2.htm, it's for PBP.

[Ingvar]

Since the DS1802 gives you temperature in half degrees, it would be easier to use the formula F = (C*9/10)+32. For negative numbers you need to convert the negative temperature to positive and reverse the formula F = 32-((ABS C)*9/10). Spotting negative numbers is easily done by looking at the highest bit. If it's set the number is negative.

TempC VAR WORD
TempF VAR WORD

IF TempC.15 THEN
TempF = 32-((ABS TempC)*9/10)
ELSE
TempF = (TempC*9/10)+32
ENDIF


You could use the ** operator to save the division. This operator makes a multiplication and an "invisible" division by 65536. 0.9 * 65536 = 58982.4, since we can only use integers we round that to 58983. Our calculation will look like......

IF TempC.15 THEN
TempF = 32-((ABS TempC)**58983)
ELSE
TempF = (TempC**58983)+32
ENDIF

/Ingvar

[Darrel Taylor]

For the EASIEST way to convert temperatures.

Try my Temperature Conversion routines for PBP.

It's an INCLUDE file that converts between Celsius, Fahrenheit and Kelvin.

HTH,
   Darrel