What memory is used for DATA @X, LONG $XXXXXX

If one uses the DATA command to write to EEPROM at program time and are writing a LONG variable, how many bytes are used in memory and what locations are used. The memory is organized in bytes and writing DATA @0, $FF writes to the 1st byte of memory. If instead DATA @0, LONG $FFFFFFFF, does this write to eeprom locations 0,1,2 and 3 or is the memory managed by the PIC such that memory location 0 is a long and the next memory location is 1 which will also be a long?

Thanks

If you write a LONG to EEPROM it will occupy 4 bytes or "locations". So if your LONG starts at 0 the next free byte/location will be at adress 4.
To be honest I'm not sure about the "order", ie little vs big endian but that's easy enough to test.

/Henrik.

This should give you some idea how it is orginized.

It explains itself. I captured the values 4 times, and the picture shows all 4 values.

Code:

---

LongVal var long
ByteVal0 var byte
ByteVal1 var byte
ByteVal2 var byte
ByteVal3 var byte


Test:
   
'%00000000 00000000 00000000 00000001
'%00000000 00000000 00000001 00000000
'%00000000 00000001 00000000 00000000
'%00000001 00000000 00000000 00000000

    longval = %00000000000000000000000000000001  '32-bit value.
               
    write 0, long longval
   
    read 0, byteval0
    read 1, byteval1
    read 2, byteval2   
    read 3, byteval3
       
    lcdout $fe,1,"LongVal:", dec longval

    lcdout $fe,$94,"10:",bin8 byteval1," ",bin8 byteval0
    lcdout $fe,$D4,"32:",bin8 byteval3," ",bin8 byteval2
   
    pause 100




    goto test

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